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Diffstat (limited to 'intl/plural.y')
-rw-r--r-- | intl/plural.y | 409 |
1 files changed, 0 insertions, 409 deletions
diff --git a/intl/plural.y b/intl/plural.y deleted file mode 100644 index 616b7c1..0000000 --- a/intl/plural.y +++ /dev/null @@ -1,409 +0,0 @@ -%{ -/* Expression parsing for plural form selection. - Copyright (C) 2000, 2001 Free Software Foundation, Inc. - Written by Ulrich Drepper <[email protected]>, 2000. - - This program is free software; you can redistribute it and/or modify it - under the terms of the GNU Library General Public License as published - by the Free Software Foundation; either version 2, or (at your option) - any later version. - - This program is distributed in the hope that it will be useful, - but WITHOUT ANY WARRANTY; without even the implied warranty of - MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU - Library General Public License for more details. - - You should have received a copy of the GNU Library General Public - License along with this program; if not, write to the Free Software - Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, - USA. */ - -/* The bison generated parser uses alloca. AIX 3 forces us to put this - declaration at the beginning of the file. The declaration in bison's - skeleton file comes too late. This must come before <config.h> - because <config.h> may include arbitrary system headers. */ -#if defined _AIX && !defined __GNUC__ - #pragma alloca -#endif - -#ifdef HAVE_CONFIG_H -# include <config.h> -#endif - -#include <stddef.h> -#include <stdlib.h> -#include "plural-exp.h" - -/* The main function generated by the parser is called __gettextparse, - but we want it to be called PLURAL_PARSE. */ -#ifndef _LIBC -# define __gettextparse PLURAL_PARSE -#endif - -#define YYLEX_PARAM &((struct parse_args *) arg)->cp -#define YYPARSE_PARAM arg -%} -%pure_parser -%expect 7 - -%union { - unsigned long int num; - enum operator op; - struct expression *exp; -} - -%{ -/* Prototypes for local functions. */ -static struct expression *new_exp PARAMS ((int nargs, enum operator op, - struct expression * const *args)); -static inline struct expression *new_exp_0 PARAMS ((enum operator op)); -static inline struct expression *new_exp_1 PARAMS ((enum operator op, - struct expression *right)); -static struct expression *new_exp_2 PARAMS ((enum operator op, - struct expression *left, - struct expression *right)); -static inline struct expression *new_exp_3 PARAMS ((enum operator op, - struct expression *bexp, - struct expression *tbranch, - struct expression *fbranch)); -static int yylex PARAMS ((YYSTYPE *lval, const char **pexp)); -static void yyerror PARAMS ((const char *str)); - -/* Allocation of expressions. */ - -static struct expression * -new_exp (nargs, op, args) - int nargs; - enum operator op; - struct expression * const *args; -{ - int i; - struct expression *newp; - - /* If any of the argument could not be malloc'ed, just return NULL. */ - for (i = nargs - 1; i >= 0; i--) - if (args[i] == NULL) - goto fail; - - /* Allocate a new expression. */ - newp = (struct expression *) malloc (sizeof (*newp)); - if (newp != NULL) - { - newp->nargs = nargs; - newp->operation = op; - for (i = nargs - 1; i >= 0; i--) - newp->val.args[i] = args[i]; - return newp; - } - - fail: - for (i = nargs - 1; i >= 0; i--) - FREE_EXPRESSION (args[i]); - - return NULL; -} - -static inline struct expression * -new_exp_0 (op) - enum operator op; -{ - return new_exp (0, op, NULL); -} - -static inline struct expression * -new_exp_1 (op, right) - enum operator op; - struct expression *right; -{ - struct expression *args[1]; - - args[0] = right; - return new_exp (1, op, args); -} - -static struct expression * -new_exp_2 (op, left, right) - enum operator op; - struct expression *left; - struct expression *right; -{ - struct expression *args[2]; - - args[0] = left; - args[1] = right; - return new_exp (2, op, args); -} - -static inline struct expression * -new_exp_3 (op, bexp, tbranch, fbranch) - enum operator op; - struct expression *bexp; - struct expression *tbranch; - struct expression *fbranch; -{ - struct expression *args[3]; - - args[0] = bexp; - args[1] = tbranch; - args[2] = fbranch; - return new_exp (3, op, args); -} - -%} - -/* This declares that all operators have the same associativity and the - precedence order as in C. See [Harbison, Steele: C, A Reference Manual]. - There is no unary minus and no bitwise operators. - Operators with the same syntactic behaviour have been merged into a single - token, to save space in the array generated by bison. */ -%right '?' /* ? */ -%left '|' /* || */ -%left '&' /* && */ -%left EQUOP2 /* == != */ -%left CMPOP2 /* < > <= >= */ -%left ADDOP2 /* + - */ -%left MULOP2 /* * / % */ -%right '!' /* ! */ - -%token <op> EQUOP2 CMPOP2 ADDOP2 MULOP2 -%token <num> NUMBER -%type <exp> exp - -%% - -start: exp - { - if ($1 == NULL) - YYABORT; - ((struct parse_args *) arg)->res = $1; - } - ; - -exp: exp '?' exp ':' exp - { - $$ = new_exp_3 (qmop, $1, $3, $5); - } - | exp '|' exp - { - $$ = new_exp_2 (lor, $1, $3); - } - | exp '&' exp - { - $$ = new_exp_2 (land, $1, $3); - } - | exp EQUOP2 exp - { - $$ = new_exp_2 ($2, $1, $3); - } - | exp CMPOP2 exp - { - $$ = new_exp_2 ($2, $1, $3); - } - | exp ADDOP2 exp - { - $$ = new_exp_2 ($2, $1, $3); - } - | exp MULOP2 exp - { - $$ = new_exp_2 ($2, $1, $3); - } - | '!' exp - { - $$ = new_exp_1 (lnot, $2); - } - | 'n' - { - $$ = new_exp_0 (var); - } - | NUMBER - { - if (($$ = new_exp_0 (num)) != NULL) - $$->val.num = $1; - } - | '(' exp ')' - { - $$ = $2; - } - ; - -%% - -void -internal_function -FREE_EXPRESSION (exp) - struct expression *exp; -{ - if (exp == NULL) - return; - - /* Handle the recursive case. */ - switch (exp->nargs) - { - case 3: - FREE_EXPRESSION (exp->val.args[2]); - /* FALLTHROUGH */ - case 2: - FREE_EXPRESSION (exp->val.args[1]); - /* FALLTHROUGH */ - case 1: - FREE_EXPRESSION (exp->val.args[0]); - /* FALLTHROUGH */ - default: - break; - } - - free (exp); -} - - -static int -yylex (lval, pexp) - YYSTYPE *lval; - const char **pexp; -{ - const char *exp = *pexp; - int result; - - while (1) - { - if (exp[0] == '\0') - { - *pexp = exp; - return YYEOF; - } - - if (exp[0] != ' ' && exp[0] != '\t') - break; - - ++exp; - } - - result = *exp++; - switch (result) - { - case '0': case '1': case '2': case '3': case '4': - case '5': case '6': case '7': case '8': case '9': - { - unsigned long int n = result - '0'; - while (exp[0] >= '0' && exp[0] <= '9') - { - n *= 10; - n += exp[0] - '0'; - ++exp; - } - lval->num = n; - result = NUMBER; - } - break; - - case '=': - if (exp[0] == '=') - { - ++exp; - lval->op = equal; - result = EQUOP2; - } - else - result = YYERRCODE; - break; - - case '!': - if (exp[0] == '=') - { - ++exp; - lval->op = not_equal; - result = EQUOP2; - } - break; - - case '&': - case '|': - if (exp[0] == result) - ++exp; - else - result = YYERRCODE; - break; - - case '<': - if (exp[0] == '=') - { - ++exp; - lval->op = less_or_equal; - } - else - lval->op = less_than; - result = CMPOP2; - break; - - case '>': - if (exp[0] == '=') - { - ++exp; - lval->op = greater_or_equal; - } - else - lval->op = greater_than; - result = CMPOP2; - break; - - case '*': - lval->op = mult; - result = MULOP2; - break; - - case '/': - lval->op = divide; - result = MULOP2; - break; - - case '%': - lval->op = module; - result = MULOP2; - break; - - case '+': - lval->op = plus; - result = ADDOP2; - break; - - case '-': - lval->op = minus; - result = ADDOP2; - break; - - case 'n': - case '?': - case ':': - case '(': - case ')': - /* Nothing, just return the character. */ - break; - - case ';': - case '\n': - case '\0': - /* Be safe and let the user call this function again. */ - --exp; - result = YYEOF; - break; - - default: - result = YYERRCODE; -#if YYDEBUG != 0 - --exp; -#endif - break; - } - - *pexp = exp; - - return result; -} - - -static void -yyerror (str) - const char *str; -{ - /* Do nothing. We don't print error messages here. */ -} |